use ascii value to perform the sort
the logic is 'a' has lowest ascii value than others
How to sort an array of characters (alphabatically) in c++??
If all the characters are the same case, then I don't believe you have to use the ascii values. You can do a comparison a %26lt; b and it will evaluate to true or false. Then do a bubble sort or whichever sort you prefer.
Here's an example I just did.
#include %26lt;iostream%26gt;
#include %26lt;cstdlib%26gt;
using namespace std;
int main()
{
char chars[] = {'a','d','b','g','e','c','f'};
int size = 7;
char temp;
for(int i = 0; i %26lt; size; i++)
for(int j = 0; j %26lt; size-1; j++)
{
if(chars[j+1] %26lt; chars[j])
{
temp = chars[j];
chars[j] = chars[j+1];
chars[j+1] = temp;
}
}
for(int i = 0; i %26lt; size; i++)
cout%26lt;%26lt;chars[i] %26lt;%26lt;" ";
return 0;
}
Reply:Read the value from an array and find its ASCII (which is easy try to read a character as integer and it will return an integer vakue which is the character's ASCII value) value and sort it using any Sorting algorithms like Bubble sort, quick sort , Radix Sort , ETC. Once the array is sorted according to the ASCII value - You now just need to read the array as a character array coz the whole array has been automatically alphabetically sorted .
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