How Could i end my array of char or my strings in c++?

i have a array like this code


for (k=Start ;k%26lt;Start+3;k++)


{ ProcessingCode[k-Start]=FinalMe...


}


ProcessingCode[Start+3]="\n";


And my FinalMessage is so much bigger than Processigcode and i didnt introduce processingcode in dynamic array and i introduce it with processingcode[100] and i want to end of array up to what i fill with data...


but it return me error ,how could i make it? thank you:)

How Could i end my array of char or my strings in c++?
You need to make the final element "NULL" -- and process until you reach the NULL pointer. Let's take for example processing until the end of a char array:





//Create our array


char *aChars;





//Now allocate our array


aChars = new char[25];





//Put values in slots 0, 1 and 2


aChars[0] = 'a';


aChars[1] = 'b';


aChars[2] = 'c';





//Now terminate our array with the special '\0' character


aChars[3] = '\0';





//Now iterate through the array until the end:


int i=0;


while( aChars[i] != '\0' ) {


ProcessData( aChars[i] );


}





-------------





Now, we can apply the exact same logic to an array of character arrays (i.e. an array of strings):





//Create our array pointer


char ** aStrings;





//Now allocate our array of character arrays pointers


aStrings = new char[25]; //up to 25 strings





//Populate as many as we want to -- let's go ahead and only do 3 for testing.


for( int i=0; i %26lt; 3; i++ ) {


aStrings[i] = new char[20]; //Each String is 20 long


}





//Put values in the 3 slots we allocated


strcpy( aStrings[0], "zero" );


strcpy( aStrings[1], "one" );


strcpy( aStrings[2], "two" );





//Now terminate our array with a NULL value


aStrings[3] = NULL;





//Now iterate through the array until the end:


int i=0;


while( aStrings[i] != NULL ) {


//This will process until we hit that null terminator.


ProcessData( aStrings[i] );


}





------





When you are all done processing free the memory you allocated with a call to delete. i.e.:





delete aChars;





In the first example.





Same logic as the examples above work if you use stack allocation and just use aChars[25] instead of allocating the memory on the heap. In that case, just skip the "new" and the "delete" commands.
Reply:do processingcode[3]='/n';


in place of


ProcessingCode[Start+3]="\n";
Reply:Your question is difficult to understand , what error are you getting what is your array size ? You need to give all info. C code is pretty difficult and a small mistake can cause major issues.