You pass a pointer to it.
void doStuff(char **pJunk) {
...
}
int main(int argc, char *argv[]) {
char junk[3][4];
... fill it in
doStuff(junk);
}
How can we pass a multidimensional array to a function in C?
Toadaly's solution doesn't tell how the function would know the array's dimensions...
Reply:#define COLUMN 3
void Dump(int buffer[][COLUMN])
{
for(int row=0; row %26lt; 5; row++)
for(col = 0; col %26lt; COLUMN; col++)
printf ("row: %d\tcol: %d\t%d\n", x, y, buffer[row][col]);
}
int main()
{
int g[5][COLUMN];
/* fill g up */
Dump(g);
return(1);
}
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