In C++, how do you convert an array of integers to form just one number?

Let's say I have an array where a[0] = 9, a[1] = 8, a[2] = 7, a[3] = 6


I want to place each element together to form just one number, so that i could have int num = 9876. Is this possible?

In C++, how do you convert an array of integers to form just one number?
Sure it's possible... a *hint* would be... Use multiples of 10!
Reply:Here is a way:





#include %26lt;stdio.h%26gt;


#define SIZE 4





int powers( num, power )


{


if ( power == 0 )


return 1;


else


{


return ( num * powers( num, power-1 ) );


}


}





int main()


{


int arr[SIZE] = { 9, 8, 7, 6 };


int i;


int num = 0;


int largest = powers( 10, SIZE );





for ( i = 0; i %26lt; SIZE; ++i )


{


largest = largest/10;


num += arr[ i ] * largest;


}





printf( "The number is: %d\n", num );


return 0;


}
Reply:Here is a function for you.





//values is the array and size is the length of the array


// do not pad the array with zeros on the left.


int combine(int* values, int size)


{


// setup and initial value as the first one in the array


int result = values[0];





// loop through all the rest of the values


// push the old numbers over by 1 place *10


// and add the new one on the end + val


for(i=1;i%26lt;size;i++)


result += result*10 + values[i];





return result;


}
Reply:You could try using:





String.Concat(x);





to create a string from the elements of array x. You would then have "9876", but it would be a string, not a number. You could then cast it into an integer easily if you needed to carry out mathematical functions on it. I'm a bit rusty, so I'm not sure whether you will need to import String.h or whether it will be included in system namespace.





Good luck.