C++ Arrays?

i have to make a c++ program using arrays, that adds 2 integers up to 20 characters long. right now, i'm stuck before i even started because my array only outputs correctly if the input number is 10 characters long. what's wrong with this?





#include %26lt;iostream%26gt;


#include %26lt;iomanip%26gt;





using namespace std;





int main()


{


int augent[20];


int index;





for(index = 0; index %26lt;20; index++)


{


augent [index]=0.0;


cout%26lt;%26lt;"Please enter augent: ";


cin%26gt;%26gt;augent[index];


cout%26lt;%26lt;endl;


cout%26lt;%26lt;"Augent is "%26lt;%26lt;augent[index]%26lt;%26lt;endl;


}


return 0;


}








Also, once this problem is solved how do i proceed with the rest of the program?





Also I ve been told I have to use strings, is that true?





I would greatly appreciate your help.

C++ Arrays?
Type | Bytes | range of values


--------------------------------------...


int 4 –2,147,483,648 to 2,147,483,647





unsigned int 4 0 to 4,294,967,295


--------------------------------------...





main problem is that you CANT have a 20 digit INT, what u need is either a __int64 (long long) or an unsigned __int64 (unsigned long long) these allow –9,223,372,036,854,775,808 to 9,223,372,036,854,775,807 and 0 to 18,446,744,073,709,551,615 respectivly as they are 8 byte,





that or choose another way to store them (maybe as a text value, as there is a c++ function to convert btw text and numbers (or just write your own))
Reply:integers have a range which they work in I think 20 characters


eg 100000000000000000000 is out of the range of an integer. Try floats I am not sure how much they hold or use strings then convert them into ints.





Also why does your array have 20 elements isnt it suposed to be 2 elements 20 char long each? maybe i dont get the question.