How do you check if a spot in a char array has a character there or not (C++)?

I'm having problems couting a character array. It couts the list of characters, plus a bunch of junk after it. So then I need to set up a while statement...





bool notChar = false;


int count = 0;


while(notChar = false) {


cout temp[count];


count++;


if(temp[count] == ???) { notChar = true; }


}





...Any ideas?

How do you check if a spot in a char array has a character there or not (C++)?
char* or char[ ] types typically use a char value of 0 to mark the end of the string.





however, "cout" will stop at this 0 automatically, so you obviously do not have a 0 at the end of the string.





the best bet would be to not use a char* or char[ ] type at all, but use a STL::string type. research the C++ standard tempalte libraries. it has a string type with everything built in.





if you must use char* or char[ ], initialize your array to all 0's and never use the final size'd spot. this is clumsy C programming though, not C++. Use the STL in C++, it prevents many bugs.
Reply:look up isalpha





something like





if (!isalpha(int(temp[count])) notChar = true;





can't recall what header file.

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