It's been a while since I've messed with C, but:
arrayName.Length();
How to know the size of a 2D array in C ?
If you have a 2D array as a pointer, you will need to be passed the size explicitly.
Does this help?
Reply:If the 2D array is declared explicitly, like this:
int array[16][8];
Then you can easily tell that the array is 16x8 (if you're looking for bytes, multiply that by sizeof(int)).
If the 2D array is declared as a pointer to a pointer, like this:
int **array;
Then you should find the place where the memory for it is allocated, and check what argument is given to the malloc function. It should look something like:
array = malloc(SIZE*sizeof(int));
I hope this helps.
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